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发表于:2008-5-11 12:57
标题:初学JAVA,在此请教!
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type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception org.apache.jasper.JasperException: Exception in JSP: /newsMain.jsp:45
42: String strSql = null;
43: strSql = "Select * from news where type=1 order by time desc";
44: rs = conn.executeQuery(strSql);
45: while (rs.next()) {
46: %> ">
48: <%
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:451)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:373)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:329)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:265)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
root cause java.lang.NullPointerException
org.apache.jsp.newsMain_jsp._jspService(newsMain_jsp.java:94)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:98)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:331)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:329)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:265)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
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